Re: Parameterized collection catch-22

From:
Daniel Pitts <newsgroup.nospam@virtualinfinity.net>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 12 Mar 2014 09:51:33 -0700
Message-ID:
<lg0Uu.13736$Nm1.6311@fx22.iad>
On 3/11/14 9:36 AM, zapanaz_googlegroups@hotmail.com wrote:

I have a parent class, AddressInfo. An abstract class. Two classes inherit from AddressInfo, ShippingInfo and BillingInfo. ShippingInfo and BillingInfo are nearly identical, and are identical for what I'm doing here.

The example code I'm posting is stripped down, in case you wonder why it's a little dumb.

I have two methods,

public void mergeBillingInfoLists(List<BillingInfo> list1, List<BillingInfo> list2) {
list1.add(1, list2.get(0));
}

And one for ShippingInfo which is identical, just with ShippingInfo where BillingInfo is.

I want to combine the two methods, which are very redundant. It seems like it should be possible, given that they have a common parent class. I can do this:

public void mergeAddressInfo(List<? extends AddressInfo> list1, List<? extends AddressInfo> list2) {
list1.add(1, list2.get(0));
}

But Java won't allow this, it won't allow the add(). All it knows about what list2 contains is that it's something that descends from AddressInfo, so even if I pass in 2 List<BillingInfo>'s, inside the code it doesn't know they're the same classes.

Does anybody offhand know a way to do this? (Without throwing away the parameterization :) )

I don't necessarily need to use this exact approach, just anything that would allow me to combine the two methods into one method. In fact I have quite a lot of this kind of redundancy in the code base I'm working with, so this is something I'm running into a lot.

Thanks for any help


There are three ways write that so it works as you desire:

Method one:
public <T> void mergeInfo(List<? super T> list1,List<? extends T> list2)

T is any type at all.
list1 can be any type of List of <T> or List of <SuperclassOfT> This
means the list1 can accept any object that is assignable *from* <T>. It
is unknown the type that it produces.

list2 can be any type of List of <T> or List of <SubclassOfT>. It will
produce objects that assignable *to* <T>.

Method two:
public <T> void mergeInfo(List<T> list1,List<? extends T> list2)

T is any type at all.
list1 can be any type of List of <T>, but not any other type parameter.
  list1 can therefor produce and accept any object assignable to or from <T>

list2 is the same as list2 from Method One

Method three:
public <T> void mergeInfo(List<T> list1,List<T> list2)

T is any type at all.
list1 can be any type of List of <T>, but not any other type parameter.
  list1 can therefor produce and accept any object assignable to or from <T>

list2 must be a List with the exact same type parameter as list1.

And finally, one last note. For any of the examples above, if you want
to ensure that you're only dealing with subclasses of AddressInfo:

public <T extends AddressInfo> void mergeInfo(... yata yata)

This says "T must be AddressInfo or a subclass thereof".

In your particular case, I would combine this with Method Three. Though
often with generic functions, you're better off with Method one.

The rule-of-thumb I use is: In your scope if you have an object that
only accepts <T> use <? super T>. If you have an object that only
produces <T>, use <? extends T>. If you have an object that produces
and accepts <T>, then use <T>. I'm talking about "produces" or
"accepts" in what you call, not what methods are available.

HTH.

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