Re: Accessing private member via subclass

From:
"Mike Schilling" <mscottschilling@hotmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Mon, 23 Nov 2009 10:47:30 -0800
Message-ID:
<heelc4$buo$1@news.eternal-september.org>
Arved Sandstrom wrote:

Mike Schilling wrote:

Patricia Shanahan wrote:

The rule that makes it illegal is the i is not even a member of
Sub,
and membership in Sub is needed to make the s.i notation valid.

"Members are either declared in the type, or inherited because
they
are accessible members of a superclass or superinterface which are
neither private nor hidden nor overridden (?8.4.8)."

http://java.sun.com/docs/books/jls/third_edition/html/names.html#6.4.3


That explains it. The analogous statement in C# is:

    10.2.1: A class inherits the members of its direct base
class.
    Inheritance means that a class implicitly contains all members
of
its
    direct base class, except for the instance constructors,
destructors
    and static constructors of the base class.

which explain the difference in behavior.


I don't want to go off on a C# tangent here, but I'm not satisfied.
The C# 3.5 docs (in various places) say things like:

A derived class has access to the public, protected, internal, and
protected internal members of a base class. Even though a derived
class inherits the private members of a base class,


Unlike in Java, where it doesn't inherit them.

it cannot access
those members. However, all those private members are still present
in the derived class and can do the same work they would do in the
base class itself. For example, suppose that a protected base class
method accesses a private field. That field has to be present in the
derived class in order for the inherited base class method to work
properly.
and

Private members are accessible only within the body of the class or
the struct in which they are declared.


In other words, in "super".

and

Nested types in the same body can also access those private members.

and

It is a compile-time error to reference a private member outside the
class or the struct in which it is declared.


In other words, in "super".

Your quoted C# language spec snippet does not in fact gainsay any of
these.


It seems to me that they all agree that the code should compile
without error.

I do not see how the nearest C# equivalent of what we have here
in Java would compile.


Here they are: try it for yourself.

public class Sub : Super
{
}
public abstract class Super
{
    private int i;

    internal void method(Sub s)
    {
        s.i = 2;
    }
}

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