Re: overloading operator delete[](void*, size_t) - possibly incorrect implementation of the language specification in Visual C++?
On Dec 20, 2:29 pm, Dobi <ha...@daiw.de> wrote:
On 20 Dez., 13:18, Chris Vine <ch...@cvine--nospam--.freeserve.co.uk>
wrote:> This approach surely can't be right, as the two argument version of
operator delete[] is obliged to provide the size of the block to be
deallocated.
Presumably what has happened is that to maintain an optimised heap
layout, the call to operator new[] returned more memory than
requested. In that case, you would need to delete the memory
allocated, not the memory requested as you propose.
I doubt very much that microsoft's compilers are as wayward as you
suggest.
Chris
The example code I posted, produces the following output with g++:
new[]: size_t=404
delete[]: size_t=404
With Microsoft Visual C++ it looks as follows:
new[]: size_t=400
delete[]: size_t=4
Further data point:
Even if C has a nontrivial destructor (I did a print), it happens. It
does invoke the
destructor the proper number of times.
Also, the size_t parameter appears to be sizeof(C). I tested this by
adding a second
int member, and the second parameter jumped to 8.
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