Re: Integer to string conversion

From:
"Jim Langston" <tazmaster@rocketmail.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 28 Apr 2008 23:55:43 -0700
Message-ID:
<bEzRj.5573$fn.1364@newsfe05.lga>
pradeep wrote:

Hello friends:

I know some people here don't like to answer C++ questions, but I
believe this is really about the underlying C code. Anyway I have
 posted as well to the other group someone suggested
("comp.lang.c++") just in case.

I think the problem is that in my C++ class, we were taught to use
cin, cout etc. but now I need to use the primitive C operations
printf etc. and I don't understand exactly how they work.

I'm trying to convert an integer into a string. Here's what I'm
trying, but when I try to output the string returned from the
function, I just get garbage. How should I be using sprintf?

Thanks.

char *App::IntToString(int i) //doesn't really rely on classes
{
    char buf[2];


Not big enough by far and disappears once IntToString finishes.

    char *out = buf;


No reason to have to do this.

    sprintf(out, "%d", i);


sprintf( buf, "%d", i );
would also work, although there are hte other problems.

    return out;


you are returning a pointer to a buffer that goes out of scope when the
function returns.

}


So, how to fix this? Simplest is to make the buffer static so it doesn't
disappear when the function returns and make it big enough. char buf[2];
is only large enough to hold "0" through "9". An integer can hold quite a
larger value, however. 10 or 11 digits I think.

char *App::IntToString(int i) //doesn't really rely on classes
{
    static char buf[12];
    sprintf(buf, "%d", i);
    return buf;
}

Shoudl fix the immediate errors, but does not fix any design issues. Such
as the fact if you called this twice in a row, both returned char*'s would
point to the same value. I.E.

char* Value1;
char* Value2;

Value1 = IntToString( 10 );
Value2 = IntToString( 11 );

std::cout << Value1 << " " << Value2;

would output 11 11 since the pointers returned by IntToString are identical,
and the static buffer was changed.

It is better to return a std::string. You can do the conversion either as is
and convert to a std::string, or use use std::stringstream. (Untested
code).

std::string App::IntToString( int i )
{
   std::stringstream Convert;
   Convert << i;
   std::string Answer;
   Convert >> Answer;

   return Convert.string();
}

Personally, I use a template for this.

    template<typename T, typename F > T StrmConvert( const F from )
    {
        std::stringstream temp;
        temp << from;
        T to = T();
        temp >> to;
        return to;
    }

    template<typename F> std::string StrmConvert( const F from )
    {
        return StrmConvert<std::string>( from );
    }

So I can do:

std::string Value = StrmConvert( 10 );

or even:

int Value = StrmConvert<int>( "10" );

Note that my StrmConvert does not have any error checking, any errors would
simply return a default constructed value. I.E. If you tried to convert
"xyz" to an int the result would be 0.
--
Jim Langston
tazmaster@rocketmail.com

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