Re: how to reverse find_if?

From:
red floyd <no.spam@here.dude>
Newsgroups:
comp.lang.c++
Date:
Sat, 17 Mar 2007 02:36:05 GMT
Message-ID:
<puIKh.3577$Qw.2740@newssvr29.news.prodigy.net>
Kai-Uwe Bux wrote:

Jim Langston wrote:

"JDT" <jdt_young@yahoo.com> wrote in message
news:vpEKh.9132$FG1.8910@newssvr27.news.prodigy.net...

red floyd wrote:

red floyd wrote:

JDT wrote:

red floyd wrote:

I think that you can use std::reverse_iterator with a pointer. See
24.1.1

typedef std::reverse_iterator<float *> rfloat_iter;
rfloat_iter p =
   std::find_if(rfloat_iter(m+6), rfloat_iter(m),
                std::bind2nd(greater_equal<float>(), 14.5));


Thanks for your help. First of all, what do you mean by 24.1.1?


Section 24.1.1 of the ISO C++ Standard (ISO/IEC 14882:2003).

I am testing your code. To check if find_if finds something, should I
use "p == rfloat_iter(m+6)" or "p == rfloat_iter(m)"?

The latter.

Besides, is the range between m+5 and m-1?


Sort of. See 24.1.1 for more details.

Your code has some compile errors. I appreciate if somebody can show
me what's the correct syntax (because I am not familiar with this
regard).


You need to #include <iterator>

I'm not surprised, I wrote it off the top of my head. I'm sure that
one of the other more knowledgeable types here can help you more than
me.

Also, as a matter of etiquette, please try not to top-post (posting all
your text above what you're replying to) -- it's frowned on in this
newsgroup. Instead, intersperse your replies with the text you're
referring to (as I did here), or after the text.


you might try this:

#include <iterator>
typedef std::reverse_iterator<float *> rfloat_iter;
const rfloat_iter rbegin = rfloat_iter(m+6);
const rfloat_iter rend = rfloat_iter(m);
rfloat_iter p =
   std::find_if(rbegin, rend,
                std::bind2nd(std::greater_equal<float>(),
                             14.5));
if (p == r_end)
   /* not found */;


Hi Red,

The compiler doesn't like the following line so the typedef statement
fails:
reverse_iterator<float *>

Thanks for your help.

Tony

I *think*, but am not positive, he meant something like:
std::vector<float*>::reverse_iterator


No, he did not: the whole point is to turn pointers (used as iterators into
a raw array) into reverse_iterators into that same array. There is no
vector in any of this.

To the OP:

The following (which is the code from red floyd) compiles on g++ and Comeau.

#include <iterator>
#include <algorithm>
#include <functional>

typedef std::reverse_iterator<float *> rfloat_iter;

int main ( void ) {
  float m[6];
  const rfloat_iter rbegin = rfloat_iter(m+6);
  const rfloat_iter rend = rfloat_iter(m);
  rfloat_iter p =
    std::find_if(rbegin, rend,
                 std::bind2nd(std::greater_equal<float>(),
                              14.5));
}

If you still can't get the code to compile, please post a short but complete
program that demonstrates the problem.


Thanks, Kai-Uwe. I suspect the OP's problem is that he didn't put the
std:: in front of the reverse_iterator in the typedef.

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