Re: Convert template argument to string

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 16 Oct 2008 05:12:42 -0700 (PDT)
Message-ID:
<27937373-3d65-4021-92c6-0d86d2226119@c60g2000hsf.googlegroups.com>
On Oct 16, 10:57 am, "Marco Nef" <maill...@shima.ch> wrote:

I'm looking for a template class that converts the
template argument to a string, so something like the
following should work:

Convert<float>::Get() == "float";
Convert<3>::Get() == "3";
Convert<HelloWorld>::Get() == "HelloWorld";

The reason I need this is that in our design every class
of a certain hierarchy has a class name that must be
unique. So far I could not find a solution for template
classes.


What do you need those names for? Why do you want for it to
work with values as well as with types?

If typeid(X).name() is not sufficient for you (not portable,
may be not human readable), you'll have to provide a string
for every class yourself.


Thanks for your replies. I know about typeid and it is not
sufficient as "typeid->name" by the standard is not persistent
and not even unique.


What do you mean by "persistent" in this case?

And in practice, if the types are restricted to those you can
actually use to instantiate a template, about the only case
where they might not be unique in practice is if the types are
defined in anonymous namespace.

Another solution would be the following:

template<typename Type> struct Convert
{
    const String &GetName(VOID) const { return Type::GetName(); }
};

template<> struct Convert<float>
{
    const String &GetName(VOID) const { return "float"; }
};

template<> struct Convert<int>
{
    const String &GetName(VOID) const { return "int"; }
};

and so on...

So any classes provided as template argument need to implement
GetName(), for the base types there are specializations. This
works, but I don't really like it.


Which is understandable. (Although you could use a macro to
generate the specializations.)

I would love a struct like:

template<typename Type> struct Convert
{
    const String &GetName(VOID) const { return XXXXXX; }
};

where XXXXXX is the question of this task :-)


The only thing anywhere like this in the standard is
typeid<Type>.name().

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James Kanze (GABI Software) email:james.kanze@gmail.com
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