Re: Operator delete question

From:
snapwink <snapwink@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 20 Oct 2009 16:30:21 -0700 (PDT)
Message-ID:
<82c8bf31-8a42-4d63-89f8-b6d35ded6b64@q40g2000prh.googlegroups.com>

/* Interface I am trying to implement */
class ISocket
{
public:
  virtual void Release() = 0;
  virtual void TCPSockMethod() = 0;

};


you just missed a virtual destructor in your interface...


Yep, I am aware of that. The interfaces we export need to be binary
compatible. If I added a virtual destructor, that would change the
interface's V-table breaking this compatibility. I don't know why the
initial interface we have does not have virtual destructor (guess they
missed it due to some reason), but we would not be able to change
that.

class TCPSocket {

...

  virtual void Release () {printf ("Socket::Release\n"); delete this;=

}

...

};


the "delete this" on your Release() call will invoke ISocket::~ISocket
() (a no-op function generated by your compiler)


Are you sure? I am calling "delete this" in Socket class. Which should
result in Socket destructor being invoked directly. And since that is
virtual, it should in-turn result in TCPSocket destructor getting
invoked. At-least on GCC this is what's happening.

int main()
{
  ISocket *pISock = static_cast <ISocket *> (new TCPSocket());
  pISock->Release();
  return 0;


Cheers

Diego Martins
HP

I am back from the dead :D

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