Re: Automatic serialization --- is it possible?

From:
"Nevin :-] Liber" <nevin@eviloverlord.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Mon, 5 Nov 2007 17:30:53 CST
Message-ID:
<nevin-407E46.13591605112007@chi.news.speakeasy.net>
In article <1194220246.418338.128250@i38g2000prf.googlegroups.com>,
 Carlos Moreno <cm_news@mailinator.com> wrote:

To simplify the task, I'm happy with a "constrained"
version of the problem --- I could have a class, say a
template class Serializable_member, such that only
the data members of that class would need to be
saved.

Example:

class Example : public Base
{
public:
     // .... customize my functionality.

private:
     int x;
     Serializable_data<int> y;
     Serializable_data<string> z;
}

And that's it --- without having to do *anything* more,
on destruction, those two data members (y and z) should
be saved on a filename that is associated with the object
that owned them.


I don't see how, given the constraints. You need something that
associates y and z with a particular instantiation of Example.

Now, if you relaxed the constraint and have the Serializable_data
constructor take a pointer or reference to the instantiation of Example
or Base, as in:

class Base
{
protected:
   template<typename T>
   struct Serializable_data
   {
      Serializable_data(Base*) { /* ... */ }
   /* ... */
   };
/* ... */
};

the rest should be doable. Not easy, mind you, but possible.

--
 Nevin ":-)" Liber <mailto:nevin@eviloverlord.com> 773 961-1620

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