Re: Best way to append std::list to itself

From:
peter koch <peter.koch.larsen@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 7 Jan 2011 06:19:17 -0800 (PST)
Message-ID:
<5780ae11-8a6b-4f95-b28f-d195203873ee@j29g2000yqm.googlegroups.com>
On 7 Jan., 12:47, James Kanze <james.ka...@gmail.com> wrote:

On Jan 6, 6:28 pm, Jorgen Grahn <grahn+n...@snipabacken.se> wrote:

On Thu, 2011-01-06, Marcel M ller wrote:

Yes, and according to the guarantees of std::list it will
always point to one past the last element in the container.


That's an interesting assertion. I don't think that the
standard is clear here: does the end iterator point to one past
the last element, always, or does it point to one past the last
element when it was called. I.e.:

    std::list<char> l;
    l.push_back('a');
    l.push_back('b');
    l.push_back('c');
    std::list<char>::iterator i = l.end();
    // i points to one past the element 'c'
    l.push_back('d');
    // i points to one past the element 'c'?
    // or one past the new last element.

I don't think that the standard is really clear here. (I don't
think it's an issue for other containers---in vector, for
example, insertion invalidates any iterators behind the point of
insertion, and thus, any end iterator.)


[snip]
Interesting subject. You are not entirely right, as the iterators will
stay valid so long as the vector has sufficient capacity.

/Peter

/Peter

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