Re: casting (void *) to (class *)

From:
Maxim Yegorushkin <maxim.yegorushkin@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Wed, 15 Apr 2009 08:00:24 -0700 (PDT)
Message-ID:
<b50e6d5b-a9df-4030-b041-641466a6b79d@c9g2000yqm.googlegroups.com>
On Apr 15, 12:58 pm, "Alf P. Steinbach" <al...@start.no> wrote:

* James Kanze:

On Apr 15, 4:04 am, "Alf P. Steinbach" <al...@start.no> wrote:

* Jonathan Lee:

But better, don't use void* pointers (except for the special
case of identifying objects in e.g. a hash table, in which
case you should make sure to have pointers to complete
objects, e.g. obtained by dynamic_cast to void*).


I'm not sure I understand this one. Do you mean just using the
pointer as the key?


Yes.

 (And how do you get a hash value for a pointer, portably?)


Wait a sec, checking Boost...

KO.

    // Implementation by Alberto Barbati and Dave Harris.
#if !BOOST_WORKAROUND(__DMC__, <= 0x848)
     template <class T> std::size_t hash_value(T* const& v)
#else
     template <class T> std::size_t hash_value(T* v)
#endif
     {
         std::size_t x = static_cast<std::size_t>(
            reinterpret_cast<std::ptrdiff_t>(v));

         return x + (x >> 3);
     }


Wow! Why can't it be as simple as:

    std::size_t x = v - static_cast<T*>(0);

?

--
Max

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