Re: template argument deduction
* boaz_sade@yahoo.com:
The correction should be (and it works with g++ 3.4, I will never use
microsoft compiler for anything ather then visual basic) is
typedef std::complex<scalar> complex_type;
// no need for the typename
typedef std::vector< complex_type > cvec_type;
// no need for typename
typedef typename cvec_type::const_iterator cvec_const_iter;
// typename must be used
typedef typename cvec_type::iterator cvec_iter;
// typenae must be used
template < typename T >
void run_it ( typename complex_param<T>::cvec_type& cvec )
{
tyename complex_param<T>::cvec_size_type const sz = cvec.size();
// dependent name must used with typename!!
for ( typename complex_param<T>::cvec_size_type idx ( 0 ); idx < sz;
++idx ) {
// dependent name must used with typename!!
std::cout << cvec [ idx ] << std::endl;
}
}
the rest of the code should not be changed..
good luck (and steer clean of MS "compliers")
Except for the bit about MS compilers that's good advice, but doesn't
address the OP's problem.
The problematic statement, commented in the original posting, doesn't
compile no matter whether you're using MS compiler or GNU compiler.
Nor should it compile.
--
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