Re: Temporary objects, l-values.

From:
"jason.cipriani@gmail.com" <jason.cipriani@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 19 Feb 2008 10:37:18 -0800 (PST)
Message-ID:
<ed342adc-1a59-4da0-b10b-8aff1f1470e3@s19g2000prg.googlegroups.com>
On Feb 19, 1:20 pm, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:

jason.cipri...@gmail.com wrote:

template <class T> T& abracadabra (const T& v) {
 union {
   T *pr;
   const T* pv;
 } u;
 u.pv = &v;
 return *u.pr;


... Why don't you simply const_cast it?


I did, in a previous post in this thread. The reason I didn't use
const_cast here is I am playing around trying to find other ways to do
that trick that don't involve explicitly casting the const away (which
also turned out to be undefined).

On Feb 19, 1:21 pm, Erik Wikstr=F6m <Erik-wikst...@telia.com> wrote:

...
  void bar() {
    Foo& f = Foo();
    f.print();
  }
...
Binding temporaries to
const references is a special rule in C++, ...


Thanks for your reply. That makes sense. It looks like I also
misunderstood "binding to non-const references" in this context -- I
had always assumed that the case of function parameters was different
from the case of reference declarations and assignments. Your example
makes sense, but to me that seems different than passing a temporary
as a non-const reference parameter to a function (where no "lifetime
extensions" need to be made to keep it valid through the entire
function call). But, I guess function parameters and variable
declarations all follow the same rules?

Jason

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