Re: Passing array by reference
john wrote:
Guys,
quick question - got a function like:
void CalculateApproach(float (&Params)[4], double (&ObjectPos)[3],
double (&VehiclePos)[4], double (&NewPos)[4])
OK, the seconds argument should come from an array but this array is
bigger than the expected 3 i.e it has 10 elements but I only need 4,5
and 6 so I tried something like:
CalculateApproach(fAppParams, &dFeatures[4], dCurVehPos, dNewVehPos);
but it fails for me. Am I trying to do something that is not allowed
Yes, essentially.
and hence should just make new array[3] and copy my values in and
then pass it into the function or can someone give me hint towards
the syntax i should be using if it can work?
You could try forcing it with a cast...
void foo(int (&ar)[3])
{
ar[0] = 1;
ar[1] = 11;
ar[2] = 111;
}
#include <cassert>
int main()
{
typedef int (*pArrayOf3int)[3];
int array[10] = {};
foo(*pArrayOf3int(array + 5));
assert(array[5] == 1);
assert(array[6] == 11);
assert(array[7] == 111);
}
V
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