Re: A C2664 error

From:
zhxzhx@gmail.com
Newsgroups:
comp.lang.c++
Date:
Fri, 21 Dec 2007 02:20:56 -0800 (PST)
Message-ID:
<8dac3f34-3388-40e5-8621-3ede81f4069f@s12g2000prg.googlegroups.com>
On 12=D4 21=C8=D5, =CF =CE=E74=CA=B123=B7=D6, Ondra Holub <ondra.ho...@p=
ost.cz> wrote:

zhx...@gmail.com napsal:

Here is a program, I want to change the way which a map use to order
elements.

struct sizemore
{
   bool operator()(const wstring &s1,const wstring &s2)
   {
           return s1.size()>s2.size();
   }
};

int dictinput(const char *filename,map<wstring,wstring> &mwdict())
{
   ...
}

int main()
{
   map<wstring,wstring> mwdict(sizemore());
   dictinput("filename",mwdict);
}

But I receive a message:
 error C2664: 'dictinput' : cannot convert parameter 2 from
'std::map<_Kty,_Ty> (__cdecl *)(sizemore (__cdecl *)(void))' to
'std::map<_Kty,_Ty> &(__cdecl *)(void)'

I'm always puzzled with parameters of function.
Could some one give me some advices?
Thanks a lot.


You need to specify comparation as 3rd parameter of template std::map.
See example below:

#include <iostream>

#include <map>
#include <string>

template<typename T>
struct CmpBySize
{
    bool operator()(const T& s1, const T& s2) const
    {
        return s1.size() < s2.size();
    }

};

typedef
    std::map<std::string, std::string, CmpBySize<std::string> >
MapStrStr;

int main()
{
    MapStrStr m;
    m["aaa"] = "3 x a";
    m["bb"] = "2 x b";
    m["z"] = "1 x z";

    const MapStrStr::const_iterator end = m.end();
    for (MapStrStr::const_iterator i = m.begin(); i != end; ++i)
    {
        std::cout << "m[\"" << i->first << "\"] = \"" << i->second <<
"\"\n";
    }

}


I have try your advice,but now the erroer information is:

cannot convert parameter 2 from 'std::map<_Kty,_Ty,_Pr>' to
'std::map<_Kty,_Ty,_Pr> &(__cdecl *)(void)

Is here anything wrong about the parameter of the fuctiocn?

int dictinput(const char
*filename,map<wstring,wstring,sizemore<wstring>> &mwdict());

And I sent a map<wstring,wstring,sizemore<wstring> object for the 3rd
parameter.

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