Re: Does object have function?

From:
James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 1 Nov 2010 10:10:22 -0700 (PDT)
Message-ID:
<e2cfb64c-6237-489b-83c7-557d9cbd8c21@30g2000yql.googlegroups.com>
On Oct 29, 1:30 am, Joshua Maurice <joshuamaur...@gmail.com> wrote:

On Oct 28, 6:02 pm, "Daniel T." <danie...@earthlink.net> wrote:

This would work:

class Base {
public:
   virtual ~Base() {}

};

class Fooer {
public:
   virtual void foo() = 0;

};

class DerivedOne : public Base, public Fooer {
public:
   void foo() { cout << "DerivedOne::foo()\n"; }

};

class DerivedTwo : public Base, public Fooer {
public:
   void foo() { cout << "DerivedTwo::foo()\n"; }

};

class DerivedThree: public Base {

};

int main() {
   Base* bps[3];
   bps[0] = new DerivedOne();
   bps[1] = new DerivedTwo();
   bps[2] = new DerivedThree();

   for ( int i = 0; i < 3; ++i ) {
      Fooer* thisOne = dynamic_cast<Fooer*>( bps[i] );
      if ( thisOne )
         thisOne->foo();
   }

}


With this multiple inheritance design, I would guess that you probably
want to virtually inherit from Fooer as well (not done in the above
code).


Why?

--
James

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