Re: Constructor call during inheritance

From:

James Kanze <james.kanze@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Sun, 07 Oct 2007 09:32:45 -0000

Message-ID:

<1191749565.408094.72420@k79g2000hse.googlegroups.com>

On Oct 6, 2:37 pm, appu <karuppaiah...@gmail.com> wrote:

Suppose class A is inherited from class B and Class B is inherited
from class C. Could anyone explain on how the C++ compiler construct
the A object and how is A object destroyed by compiler when it is out
of scope. Can anyone explain what does the compiler do in these
process?

The rule is that the compiler generates calls to the base class
constructors (using the initialization arguments if there are
any, and the default constructor otherwise) and all member
objects before entering into its own body. Thus, in this case,
the compiler will generate a call to the constructor of B at the
top of the constructor of A. (The same thing happens with B, of
course, so the constructor of B calls the constructor of C.)

Destruction works the same way, except that the calls to the
base class destructors are at the end of the derived class
constructor.

If this isn't described in your basic C++ text, it's time to get
a different text.

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