whats wrong with this code? (template class) - corrected

From:
Anonymous <no.reply@here.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 03 Sep 2007 12:21:35 +0100
Message-ID:
<S-mdnctX69BAbUbbnZ2dnUVZ8v-dnZ2d@bt.com>
I have been trying to write a template class for a shared memory
container, over the last few days - but I keep getting numerous compiler
errors e.g:

Error: syntax error : identifier 'myStaticShmemAllocator<void>'
Error: 'AllocationPolicy' : undeclared identifier

Here is the truncated code below -

// template Header file
extern shared_memory static_shmem;
extern shared_memory dyn_shmem;

template <class T>
struct myStaticShmemAllocator
{
     static T* Allocate(const size_t blocksize, const bool zeroed=true)
     {
         return static_shmem.allocate(blocksize, zeroed);
     }

     static void DeAllocate(T *ptr)
     {
         if(ptr);
             static_shmem.free(ptr) ;
     }
};

template <class T>
struct myDynamicShmemAllocator
{
     static T* Allocate(const size_t blocksize, const bool zeroed=true)
     {
         return dyn_shmem.allocate(blocksize, zeroed);
     }

     static void DeAllocate(T *ptr)
     {
         if(ptr);
             dyn_shmem.free(ptr) ;
     }
};

template <class ValueType, template <class SharedMemoryType> class
AllocationPolicy= myStaticShmemAllocator<void> >
class myShmemHashTable
{
     //Impl
};

//////// Code to test templates
struct MyStruct { int x; int y;};

int main(int argc, char* argv[])
{
    //implicit creation in static shmem (using dflt tplt arg)
    myShmemHashTable<MyStruct> a_static ;

    //explicit creation in static shmem
    myShmemHashTable<MyStruct, myStaticShmemAllocator<void> > a1_static ;

    //explicit creation in dynamic shmem
    myShmemHashTable<MyStruct, myDynamicShmemAllocator<void> > a_dynamic;
}

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