Re: Why the simple code can not compile?

From:
 James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 21 Sep 2007 08:37:49 -0000
Message-ID:
<1190363869.710465.307490@50g2000hsm.googlegroups.com>
On Sep 20, 6:17 pm, Jack <junw2...@gmail.com> wrote:

On Sep 19, 11:49 pm, Neelesh Bodas <neelesh.bo...@gmail.com> wrote:

On Sep 20, 11:25 am, Jack <junw2...@gmail.com> wrote:

#include "string.h"
#include <iostream>
using namespace std;
int main()
{
        char buf[1024] = "This is a test.";
        int len = 1024;
        bzero(buf, len);
        cout<<"buf::"<<buf<<endl;
}

The error is:
line 8: Error: The function "bzero" must have a prototype.
1 Error(s) detected.

I tried to compile it on Solaris SUN.


bzero was declared in C header 'strings.h'. I am not sure if C++
header strings.h declares it, but othe point to note is that this
function is deprecated, and it is suggested (by 'man bzero') that
memset be used instead.


    [...]

Thanks. But it works fine on Linux when I used g++. And it is
defined in <string.h> on Linux.


Which is an error. Neither C nor Posix allow <string.h> to
contain the symbol bzero in any form; according to the
standards, the following program should compile and run
everywhere, both as C and as C++:

    #define bzero "Hello, World!"

    #include <string.h>
    #include <stdio.h>

    int
    main()
    {
        printf( "%s\n", bzero ) ;
        return 0 ;
    }

(Curiously, on my Linux, it compiles as C, but not as C++. So
presumably, there are some #ifdef's somewhere which mean that
the symbol is not defined if you invoke the standard compliant C
compiler. And that something isn't being defined correctly when
you invoke the standard compliant C++ compiler; a bug report is
probably in order.)

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