Re: Need your experience: is "(void)param;" to avoid unused variable warnings well known for you?

From:

Victor Bazarov <v.bazarov@comcast.invalid>

Newsgroups:

comp.lang.c++

Date:

Mon, 02 Apr 2012 11:50:19 -0400

Message-ID:

<jlchrr$i57$1@dont-email.me>

On 4/2/2012 10:01 AM, Qi wrote:

On 2012-4-2 21:49, Victor Bazarov wrote:

I've seen that trick usually used in (a) a larger function than just one
empty line and one line of comment, and (b) in presence of some reason
to keep the argument name, like alternative configurations
(Debug/Release for instance):

I don't understand (a).
Can you give some example code?

*You* gave the example code. In your code the function had effectively
an empty body. In that case there is no need to have "ignore"
templates, "UNUSED_PARAMETER" macros, or any other BS. Just drop the
argument altogether.

I am talking any reasonable function that actually is supposed to do
something. The "code example" is below.

void someFunction(int argumentUsedOnlyInDebug)
{
... // some code
#ifdef NDEBUG
(void)argumentUsedOnlyInDebug;
#else
... // some code that uses argumentUsedOnlyInDebug
#endif
... // more code
}

Any suggestions for a better alternative?

I think one more readable way is using some marco?

#define UNUSED_ARG(arg) (void)arg

UNUSED_ARG(argumentUsedOnlyInDebug);

It's less confusing than
(void)argumentUsedOnlyInDebug;

<shrug> Same difference.

V
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