Re: passing virtual member function to templates
g3rc4n@gmail.com wrote:
is it possible to do something like this
template<class T, class FUN>
void foo(T& t, const FUN& f){
f(t);
}
template<class T, class FUN>
void fooo(T& t, const FUN& f){
Did you mean to name it differently?
t->f();
If 'f' is a member, then the syntax is
(t.*f)(); // notice the . not -> since your 't' is a ref
}
struct base{
virtual ~base(){}
virtual void say()=0;
};
struct dir : public base{
void say(){
std::cout << "hi" << std::endl;
}
};
void bar(){
base* ptr = new dir;
foo(ptr,std::mem_fun(base::say));
You don't need 'std::mem_fun'. Try
foo(ptr, &base::say);
delete ptr;
}
or are virtual functons something that templates can't handle?
They should be able to. You got some cleanup to do in your code. Try
rewriting the second 'foo' template as
template<class T, class F> void foo(T& t, F& f)
{
(t.*f)();
}
V
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