Re: Derived Class Constructors

From:
Greg Herlihy <greghe@pacbell.net>
Newsgroups:
comp.lang.c++
Date:
Wed, 02 May 2007 23:54:26 GMT
Message-ID:
<C25E72BE.89ED%greghe@pacbell.net>
On 5/2/07 2:46 PM, in article
1178142398.146346.276500@n59g2000hsh.googlegroups.com, "nozyrev"
<drmapando@gmail.com> wrote:

I apologize in advance if this is a very dumb question. I've been
struggling with this problem for some time: I have an abstract base
class called Base and n derived classes D1, D2, ....Dn. I would like
to have a constructor for each derived class that takes any of the
other derived classes as an argument so that these statements are
valid:

D1 d1;
D2 d2;

D3 d3a(d1);
D3 d3b(d2);

What is the syntax that I have to use for those statements to compile.
I realize that, for any given derived class i, I can't use Di (const
Base& b) as the constructor. Do i need to use virtual constructors? If
so, how?


No, but a class template and some typedefs might help. Something along the
lines of:

    class Base
    {
    public:
        virtual ~Base() {}
        virtual void f() = 0;
    };

    template <int I>
    class D : public Base
    {
    public:
        D() {}
        D(const D& d ) {}

        template <int I2>
        D(const D<I2>& d) {}

        // to do: add operator=

        void f() {}
    };

    typedef D<1> D1;
    typedef D<2> D2;
    typedef D<3> D3;

    int main()
    {
        D1 d1;
        D2 d2;

        D3 d3a(d1);
        D3 d3b(d2);
    }

Greg

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