Will "using declaration" introduce a conflict issue if we have a local function with an identical signature?

From:
junyangzou <zoujyjs@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 16 Aug 2013 21:02:45 -0700 (PDT)
Message-ID:
<ab3d8ecd-f47a-44e5-950b-796433b5bb15@googlegroups.com>
Consider the following code( an excerpt from "Effective C++, 3rd" Item 33 ):

    #include <iostream>
    using namespace std;

    class Base{
        private:
            int x;
        public:
            virtual void mf1() = 0;
            virtual void mf1(int){
                cout << "mf1(int) in base" << endl;
            }

            virtual void mf2(){
                cout << "mf2 in base" << endl;
            }

            void mf3(){
                cout << "mf3 in base" << endl;
            }

            void mf3(double){
                cout << "mf3(double) in base" << endl;
            }
    };

    class Derived: public Base {
        public:
            using Base::mf1; // make all things in Base named mf1 and mf3
            using Base::mf3; // visible (and public) in Derived's scope

            virtual void mf1(){
                cout << "mf1 in derived" << endl;
            }
            
            void mf3()----------------------------------(?)
            {
                cout << "mf3 in derived" << endl;
            }
            
            void mf4(){
                cout << "mf4 in derived" << endl;
            }
    };

    int main(){
        Derived d;
        int x = 0;
        d.mf1(); // still fine, still calls Derived::mf1
        d.mf1(x); // now okay, calls Base::mf1
        d.mf2(); // still fine, still calls Base::mf2
        d.mf3(); // fine, calls Derived::mf3
        d.mf3(x); // now okay, calls Base::mf3
        cin.get();

        return 0;
    }

Notice that the local mf3() has an identical signature with the synonym mf3() introduced by using Base::mf3. But this code will not get any complainant with g++.

And here in http://msdn.microsoft.com/zh-cn/library/was37tzw(v=VS.71).aspx.

Quote:
If a set of local declarations and using-declarations for a single name are given in a declarative region, they must all refer to the same entity, or they must all refer to functions. For example:
// functions_in_namespaces1.cpp
// C2874 expected
namespace B
{
    int i;
    void f(int);
    void f(double);
}

void g()
{
    int i;
    using B::i; // error: i declared twice
    void f(char);
    using B::f; // ok: each f is a function
}
In the example above, the using B::i statement causes a second int i to be declared in the g() function. The using B::f statement does not conflict with the f(char) function because the function names introduced by B::f have different parameter types.

So, back to the title, will using introduce a conflict?

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