Creating type erasure

From:
Kelvin Chung <kelvSYC@mac.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 5 Jan 2012 09:04:31 -0800 (PST)
Message-ID:
<2012010423020773604-kelvSYC@maccom>
Suppose I have a class Base and three derived classes, Derived1,
Derived2, and Derived3. Suppose I also have this thing:

class Result {
    boost::shared_ptr<Base> ptr; // This will always be a Derived1 or
a
Derived2 pointer, never Derived3
public:
    int getProperty();
};

The value returned from getProperty() can be determined at compile-time
(ie. all Derived1 return the same value and all Derived2 return the
same value) - the limitation of Result::ptr to Derived1 or Derived2
pointers is that this property is not well-defined for Derived3. The
question I have is in implementing getProperty().

Suppose I have this class:

template <class Derived>
class DerivedProperty;

template<>
class DerivedProperty<Derived1> : public boost::integral_constant<int, 1>
{};

template<>
class DerivedProperty<Derived2> : public boost::integral_constant<int, 2>
{};

(BTW, How do you ensure that DerivedProperty is never instantiated with
Derived3 due to its not-well-definedness, Base due to its
incompleteness, or any unrelated class due to its unrelatedness?)

As Result::ptr will always be a Derived1 or a Derived2 pointer,
getProperty() should return DerivedProperty<Derived1>::value or
DerivedProperty<Derived2>::value, where appropriate. Except that
Result doesn't have any information on which subclass the pointer
should be.

From reading about how you can do type erasure in C++, I think I should

do something like this:

class Result {
    struct ResultBase {
        virtual boost::shared_ptr<Base> getPtr() = 0; //
In case the ptr
from before is needed elsewhere
        virtual int getProperty() = 0;
    };

    template <class Derived>
    struct ResultModel : public ResultBase {
        // Has a constructor that takes in the pointer, virtual
destructor, etc.
        boost::shared_ptr<Derived> ptr;
        boost::shared_ptr<Base> getPtr() { return ptr; }
        int getProperty() { return DerivedProperty<Derived>::value;
}
    };
public:
    template <class Derived>
    Result(const boost::shared_ptr<Derived>& ptr) : impl(new
ResultModel<Derived>(ptr));

    int getProperty() { return impl.getProperty(); }
private:
    boost::shared_ptr<ResultBase> impl;
};

I believe that should be the proper way to do what I have described,
which retains enough flexibility that I can, say, later define a
Derived4 with a well-defined DerivedProperty, and not have to modify
Result. Is this true, and what other things should I be aware of if it
is?

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