Re: What's the different betteen pure virtual function and virtual function

From:
Lars Uffmann <aral@nurfuerspam.de>
Newsgroups:
comp.lang.c++
Date:
Tue, 03 Jun 2008 11:59:58 +0200
Message-ID:
<6akirmF38hpbfU1@mid.dfncis.de>
Jack wrote:

I did not get clear the different betteen them,


Given there's no errors in the code below (am not familiar enough with
virtual to know for sure on all the calls), I can provide my input:

for example:
[..]
        virtual ~Base();
        virtual void pure() = 0;

inline void Base::pure()
{
    std::cout << "Base::pure() called\n";
}


I think the pure() = 0 assignment in the class definition has no effect
since you later define the function, actually I'm not even sure if it is
allowed by the compiler.

class Derived: public Base
{
    public:
        virtual void pure();
};


This defines the new function for Derived which gets called if you call
pure() for an object of type Derived.

inline void Derived::pure()
{
    Base::pure();
    std::cout << "Derived::pure() called\n";
}

This first calls the Base class pure() and then adds its own code.

    derived.pure();

This calls Derived.pure() (which in turn calls Base.pure() first),
output will be:
Base::pure() called
Derived::pure() called

    derived.Base::pure();

This calls Base.pure() for object derived, output
Base::pure() called

    dp->pure();
    dp->Base::pure();

These two calls do exactly the same, just with a pointer as variable,
instead of an object.

I'm not sure I understand your problem?

    Lars

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