Re: class that have a member of type that's derived from it.

From:
"charleyb123@gmail.com" <charleyb123@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
22 Jul 2006 14:25:12 -0400
Message-ID:
<1153582643.494646.73170@p79g2000cwp.googlegroups.com>

Mirko Puhic wrote:

Is there a way to properly do this?

struct Derived;

struct Base{
Derived der;
};

struct Derived: public Base{

};


As others mentioned, watch for "recursion" on
containment (you can't have an object that
contains itself which contains itself which
contains itself, ...ad infinitum )

But, if you're talking about some "utility"
class of derived type (perhaps it has no state,
or perhaps a static will do), you can try
something like:

<code>
struct Derived;
struct Base {
  public:
    virtual const Derived& getDerived(void) const = 0;
    void someFunc(void) {
      // ...call "getDerived()" all you want in here.
    }
};
struct Derived : public Base {
  static const Derived MY_INSTANCE_;
  public:
    virtual const Derived& getDerived(void) const {
      return MY_INSTANCE_;
    }
};
</code>
:%s/struct/class/g

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