Re: Rewriting clone() to return a boost::shared_ptr ?

From:
Alan Johnson <alanwj@no.spam.stanford.edu>
Newsgroups:
comp.lang.c++.moderated
Date:
17 May 2006 05:27:31 -0400
Message-ID:
<e4e3he$a62$1@news.Stanford.EDU>
helix wrote:

Hi,

Are there any issues relating to writing clone() so that it returns a
smart pointer (e.g. boost::shared_ptr) rather than a raw pointer? For
example, if I have a virtual base class, A, which exposes a clone
function, and a class, B, which is dervied from A, will my 'smart'
clone() do what I expect it to do ?


Yes, that will work fine. There is, however, one drawback, in that you
cannot use covariant return types. Consider the following:

class A
{
public:
    virtual A* clone() = 0;
};

class B
{
public:
    virtual B* clone(); // Covariant return type.
};

There may be cases where you have a pointer to B, and you want to clone
the object to get another pointer to B, perhaps to do something through
some B specific member functions. Only pointers and references can be
covariant, however. Consider the following:

class A
{
public:
    virtual boost::shared_ptr<A> clone() = 0;
};

class B
{
public:
    virtual boost::shared_ptr<B> clone(); // Can't do this! Not a pointer.
};

--
Alan Johnson

      [ See http://www.gotw.ca/resources/clcm.htm for info about ]
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